Question

How do you solve `x^2 + 6x + 2 = 0` using completing the square?

Answer 1

A square is allways of the form `x^2+2ax+a^2`

Explanation:

Completing the square is you take half of the number `2a` with x and square it, which would be `x^2+6x+9`, but to even out with the `2` you've got, you write `2=9−7`:
`x^2+6x+9−7=0→`
`(x+3)^2−7=0→(x+3)^2=7→`
`x+3=±√7→x_12=−3±√7`