# How do you solve x^2 + 6x + 2 = 0 using completing the square?

A square is allways of the form ${x}^{2} + 2 a x + {a}^{2}$
Completing the square is you take half of the number $2 a$ with x and square it, which would be ${x}^{2} + 6 x + 9$, but to even out with the $2$ you've got, you write 2=9−7:
x^2+6x+9−7=0→
(x+3)^2−7=0→(x+3)^2=7→
x+3=±√7→x_12=−3±√7