How do you solve #x^2=6x-25# using the quadratic formula?

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Answer 1 · 2017-04-18T09:06:36

#x=3+4i# or #3-4i#

#x^2=6x-25# can be written as #x^2-6x+25=0#

Quadratic formula gives the solution of quadratic equation #ax^2+bx+c=0# as

#x=(-b+-sqrt(b^2-4ac))/(2a)#

Hence solution of #x^2-6x+25=0# is

#x=(-(-6)+-sqrt((-6)^2-4×1×25))/(2×1)#

= #(6+-sqrt(36-100))/2#

= #(6+-sqrt(-64))/2#

= #(6+-8i)/2#

= #3+-4i#

i.e. #x=3+4i# or #3-4i#