How do you solve #x^2=6x-25# using the quadratic formula?

1 Answer
Apr 18, 2017

Answer:

#x=3+4i# or #3-4i#

Explanation:

#x^2=6x-25# can be written as #x^2-6x+25=0#

Quadratic formula gives the solution of quadratic equation #ax^2+bx+c=0# as

#x=(-b+-sqrt(b^2-4ac))/(2a)#

Hence solution of #x^2-6x+25=0# is

#x=(-(-6)+-sqrt((-6)^2-4×1×25))/(2×1)#

= #(6+-sqrt(36-100))/2#

= #(6+-sqrt(-64))/2#

= #(6+-8i)/2#

= #3+-4i#

i.e. #x=3+4i# or #3-4i#