How do you solve #x^2 + 6x + 8 = 0# graphically?

1 Answer
A. S. Adikesavan
Mar 21, 2016

Make a graph of the parabola y = #x^2+6x+8#. The parabola cuts the x-axis at #(x_1, 0)# and #(x_2, 0)#, giving solutions #x=x_1,x_2#.
.#x_1 = -2 andx_2=-4.#

Explanation:

The parabola for the rearranged equation #(x+3)^2=y+1,# has vertex at #(-3, -1)#.It is in the 4th quadrant.

The axis of the parabola is x =#-3#, parallel to y-axis.

It will intersect x-axis at #(-2, 0) and (-4, 0)#.

Related questions
See all questions in Quadratic Functions and Their Graphs
Impact of this question
4849 views around the world
You can reuse this answer
Creative Commons License