How do you solve #x^2=6x-9# using the quadratic formula?

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Answer 1 · 2016-03-19T16:18:57

The answer is #x=3#

If we move all terms to left we get:

#x^2-6x+9=0#

which according to a formula #(a-b)^2=a^2-2ab+b^2# can be written as:

#(x-3)^2=0#

A square of an expression is zero if and only if this expression is zero, so we get:

#x-3=0#

Finally after moving #-3# to the right side we get the answer #x=3#