How do you solve #x^2 + 8x = 0#?

1 Answer
Jun 8, 2016

Answer:

#x=-8,0#

Explanation:

Factor an #x# term from both terms on the left-hand side.

#x(x+8)=0#

Now that we have two separate terms being multiplied and equaling #0#, the terms being #x# and #(x+8)#, we know that either one of these terms must be equal to #0#.

So, we have #x=0# or #x+8=0#, so the two solutions are #x=-8,0#.