How do you solve #x^2+8x=12# using the quadratic formula?

1 Answer
Jul 9, 2015

Answer:

#x ={-4+2sqrt(7) , -4-2sqrt(7)}#

Explanation:

The equation is #x^2-8*x-12=0#
The quadratic equation is:
#x =( -b +- sqrt(b^2-4*a*c)) / (2*a) #
Here, a = 1, b = 8, c = -12
Substituting these values,

#x = (-8 +- sqrt((-8)^2 + 48)) / (2*1) = (-8 +- sqrt(112)) / 2 = -4+-2sqrt(7)#

Thus the answer is #x ={-4+2sqrt(7) , -4-2sqrt(7)}#