# How do you solve x^2-8x=-16?

Mar 12, 2018

$x = 4$

#### Explanation:

${x}^{2} - 8 x = - 16$

First, you move all the terms to the left side by adding 16 to both sides
${x}^{2} - 8 x + 16 = - 16 + 16$
${x}^{2} - 8 x + 16 = 0$

Then you factor
$\left(x - 4\right) \left(x - 4\right) = 0$

Simplify
${\left(x - 4\right)}^{2}$

Solve
${\left(x - 4\right)}^{2} = 0$
$x = 4$