How do you solve #x^2−8x+16=0# using the quadratic formula?

1 Answer
Feb 22, 2017

Answer:

#x=4#

Explanation:

The quadratic formula is defined by:
#x=(-b((+/-)sqrt(b^2-4ac)))/(2a)#
where #a# is the coefficient in front of #x^2#, #b# is the coefficient in front of #x#, and c is the last coefficient.

Plugging in 1 for a, -8 for b, and 16 for c:

#x=(8((+/-)sqrt(64-4(1)(16))))/(2(1))#

Simplify:

#x=(8((+/-)sqrt(0)))/(2(1))#

#sqrt0=0# and the positive and negative of 0 is just 0. So it becomes:

#x=8/2=4#