How do you solve # x^2 – 8x = –16# by completing the square?
1 Answer
Aug 1, 2017
Explanation:
#rArrx^2-8x+16=0#
#"completing the square involves adding half the coefficient"#
#"of the x-term squared to " x^2-8x#
#"that is "(-4)^2=16#
#x^2-8x+16" is already in that form"#
#rArr(x-4)^2=0#
#rArrx=4" of multiplicity 2"#
