# How do you solve x^2 - 8x + 2 = 0 using the quadratic formula?

Jun 3, 2017

7.74, 0.26

#### Explanation:

As per quadratic formula, $x = \frac{- b \pm \sqrt{{b}^{2} - 4 a c}}{2 a}$ here, a = 1, b = - 8 & c= 2

Put all these values, we get $x = \frac{- \left(- 8\right) \pm \sqrt{{\left(- 8\right)}^{2} - 4 \cdot 1 \cdot 2}}{2 \cdot 1}$

$\Rightarrow x = \frac{+ 8 \pm \sqrt{64 - 8}}{2}$

$\Rightarrow x = \frac{8 \pm \sqrt{56}}{2}$

$\Rightarrow x = \frac{8 \pm 7.48}{2}$

$\Rightarrow x = \frac{8 + 7.48}{2} , \frac{8 - 7.48}{2}$

$\Rightarrow x = \frac{15.48}{2} , \frac{0.52}{2}$

$\Rightarrow x = 7.74 , 0.26$