How do you solve #x^2 - 8x = 20#?

1 Answer
Apr 11, 2018


x= -10, 2


First, take the 20 to the other side so the equation is equal to 0. Now the equation should look like this: #x^2-8x-20=0#. Now factor the equation using the big X. What multiplies to -20 and adds to -8? The factors should be (x-10) and (x+2). To find what x is equal to make the factors equal to 0. (x-10)=0 is 10 and (x+2)=0 is -2.