# How do you solve x^2 - 8x - 20 = 0?

Feb 17, 2016

$\Rightarrow {x}^{2} - 8 x - 20 = \left(x - 10\right) \left(x + 2\right) = 0$
hence (x - 10 ) = 0 $\Rightarrow x = 10 \text{ or } \left(x + 2\right) = 0 \Rightarrow x = - 2$