# How do you solve x^2 + 9x + 9 = 0?

$x = \frac{- 9 \pm 3 \sqrt{5}}{2}$
${x}^{2} + 9 x = - 9$
${x}^{2} + 9 x + \frac{81}{4} = - 9 + \frac{81}{4}$
${\left(x + \frac{9}{2}\right)}^{2} = \frac{45}{4}$
$\left(x + \frac{9}{2}\right) = \frac{\pm 3 \sqrt{5}}{2}$
$x = \frac{- 9 \pm 3 \sqrt{5}}{2}$