# How do you solve #x^2 + x +10 = 0# using the quadratic formula?

##### 3 Answers

Use the quadratic formula to find roots:

#x =-1/2+-sqrt(39)/2 i#

#### Explanation:

It has discriminant

#Delta = b^2-4ac = 1^2-(4*1*10) = 1-40 = -39#

Since this is negative, this quadratic equation has no Real roots.

It has a Complex conjugate pair of roots given by the quadratic formula:

#x = (-b+-sqrt(b^2-4ac))/(2a)#

#=(-b+-sqrt(Delta))/(2a)#

#=(-1+-sqrt(-39))/2#

#=(-1+-sqrt(39)i)/2#

#=-1/2+-sqrt(39)/2 i#

zero

#### Explanation:

You type into the calculator this:

x=-1+√*1*10/2*1

This equals to zero because a surd cannot be a negative number. (Some equations cannot be solved and this is one of them)

#### Explanation:

#color(blue)(x^2+x+10=0#

This is a Quadratic equation (in form

#color(brown)(x=(-b+-sqrt(b^2-4ac))/(2a)#

Remember that

Where,

#color(red)(a=1,b=1,c=10#

And don't be afraid with the formula!

Oh! we cannot find the square root of

(in form

So,