How do you solve #x^2 + x - 8 = 4# by factoring?

1 Answer
Aug 19, 2016

#x=3# or #x=-4#

Explanation:

Given
#color(white)("XXX")x^2+x-8=4#

#rArr#
#color(white)("XXX")x^2+x-12=0#

Factoring
#color(white)("XXX")(x-3)(x+4)=0#

#rArr#
#color(white)("XXX"){:((x-3)=0,color(white)("XX")orcolor(white)("XX"),(x+4)=0), (rarrx=3,,rarrx=-4):}#