# How do you solve #x^2 + y^2 = 9# and #x^2 – 3y = 9#?

##### 1 Answer

Sep 4, 2015

Solution is (-3,0), (3,0) and (0,-3)

#### Explanation:

Solving algebraically, it would be

For y=0, the equation of circle gives x= 3, -3, hence two of the points are (-3,0) and (3,0)

For y=-3, the circle equation gives x=0, hence the third point is (0,-3)