Question

How do you solve `x-2y= -3` and `x+6y= 1` using substitution?

Answer 1

`y=1/2`
`x=-2`

Explanation:

You can rearrange either the first or second equation making `x` the subject.
Rearranging the first equation:

`x-2y=-3`
`x=2y-3`

Substitute this `x` equation into the `x` in the second equation:

`x+6y=1`
`(2y-3)+6y=1`
`8y-3=1`
`8y=4`
`y=1/2`

Then substitute this `y` equation into either the `x` equation:

`x=2y-3`
`x=2(1/2)-3`
`x=1-3`
`x=-2`