# How do you solve x-2y= -3 and x+6y= 1 using substitution?

May 1, 2018

$y = \frac{1}{2}$
$x = - 2$

#### Explanation:

You can rearrange either the first or second equation making $x$ the subject.
Rearranging the first equation:

$x - 2 y = - 3$
$x = 2 y - 3$

Substitute this $x$ equation into the $x$ in the second equation:

$x + 6 y = 1$
$\left(2 y - 3\right) + 6 y = 1$
$8 y - 3 = 1$
$8 y = 4$
$y = \frac{1}{2}$

Then substitute this $y$ equation into either the $x$ equation:

$x = 2 y - 3$
$x = 2 \left(\frac{1}{2}\right) - 3$
$x = 1 - 3$
$x = - 2$