How do you solve (x-3)^2-18=0?

Jun 6, 2017

$x = + 7.243 \mathmr{and} x = - 1.243$

Explanation:

As the equation in given there is no $x$ term.

Find the square root of both sides:

${\left(x - 3\right)}^{2} - 18 = 0$

${\left(x - 3\right)}^{2} = 18$

$x - 3 = \pm \sqrt{18}$

$x = + \sqrt{18} + 3 = + 7.243$
$x = - \sqrt{18} + 3 = - 1.243$