# How do you solve #(x-3)^2=3(x-3)#?

##### 1 Answer

#### Explanation:

#(x-3)^2=3(x-3)#

#x^2-6x+9=3x-9#

#x^2-9x+18=0#

#(x-6)(x-3)=0#

Hence

#x=6" "# or#" "x=3#

Hope it helped!

#(x-3)^2=3(x-3)#

#x^2-6x+9=3x-9#

#x^2-9x+18=0#

#(x-6)(x-3)=0#

Hence

#x=6" "# or#" "x=3#

Hope it helped!

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