# How do you solve x^3 - x^2 - 12x = 0?

Mar 15, 2016

You can first factor out an x from each term to the left of the =.

#### Explanation:

$x \left({x}^{2} - x - 12\right) = 0$

Solve by factoring:

$x \left(x - 4\right) \left(x + 3\right) = 0$

$x = 0 , 4 \mathmr{and} - 3$

Hopefully this helps.