# How do you solve (x+3)(x-6)=0?

Jun 28, 2018

$x = - 3 \mathmr{and} x = 6$

#### Explanation:

any number multiplied by $0$ is $0$.

this means that either $x + 3$ or $x - 6$ can be $0$ for $\left(x + 3\right) \left(x - 6\right)$ to be $0$.

if $x + 3 = 0$, then $x = - 3$

if $x - 6 = 0$, then $x = 6$

hence, $x$ can either be $- 3$ or $6$.