How do you solve #|x+ 30|= 4x#?
x = 10
- we have to find, when the absolute value (ABS) is more than zero and when less
zero point for this ABS is x=-30
- then we will solve this problem for 2 intervals, one interval when ABS is possitive and one when ABS is negative
(in this interval ABS is negative therefore we write -(x+30) instead of ABS)
(in this interval ABS is possitive therefore we write (x+30) instead of ABS)