# How do you solve #-x + 3y =10#, #x+y=2# by graphing and classify the system?

##### 2 Answers

Two unknowns and two equations

#### Explanation:

Add these equations first:

If

The first equation (GRAPH) graph{(10+x)/3 [-10, 10, -5, 5]}

The second equation (GRAPH) graph{2-x [-10, 10, -5, 5]}

Together: graph{(-x+3y-10)(x+y-2)=0 [-10, 10, -5, 5]}

Se below for solution by (only) graphing

#### Explanation:

Pick a pair of sample points for the equation

Pick a pair of sample points for the equation

Plot the points for each equation and draw a line through the pair for each:

Read the solution as the intersection point directly from the graph: