Question

How do you solve `((x^3y)/(2z))^2`?

x=2, y=-4, and z=-5

Answer 1

`256/25`

Explanation:

By plugging in the values `x=2`, `y=-4` and `z=-5`, we obtain:

`(((2)^3(-4))/(2(-5)))^2 = ((-32)/-10)^2=(16/5)^2=256/25.`