How do you solve #|x+45| = -6#?

1 Answer
Jun 22, 2018

Answer:

# x in phi#

Explanation:

we have #|x+45|=-6#
now we have two cases

  • Case 1(#(x+45)>=0;x>=-45#........(a)
    #(x+45)=-6#
    #x=-6-45; x=-51#.........(b)
    from (a) and (b) we get
    #x in phi#
  • Case 2(#(x+45)<0;x<-45#......(d)
    #-(x+45)=-6#........(a negative sign is there because for any value of x<-45,(|A|), A will be negative)
    now we get #x=-39#..............(e)
    Again from (d)and (e)
    # x in phi#
    hence there is no real solution for x
    i.e. #x in phi#