# How do you solve #(x-5)^2=4#?

##### 3 Answers

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#### Explanation:

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**Method 1-**

**Method 2-**

**Method 3-**

Graphical Approach

Plot

#### Answer:

#### Explanation:

To 'undo' the square on the left side.

#color(blue)"take the square root of both sides"#

#sqrt((x-5)^2)=+-sqrt4#

#rArrx-5=+-2larrcolor(red)" there are 2 solutions"#

#• x-5=+2#

#rArrx=2+5#

#rArrx=7to(color(red)(1))#

#• x-5=-2#

#rArrx=-2+5#

#rArrx=3to(color(red)(2))#

#color(blue)"As a check"# Substitute these values into the left side of the equation and if equal to the right side then they are the solutions.

#x=7to(7-5)^2=4=" right side"#

#x=3to(3-5)^2=4=" right side"#

#rArrx=3" or "x=7" are the solutions"#