How do you solve # (x-5)^2=4#?

2 Answers
Jun 15, 2017

Answer:

Solution: #x=7 or x=3#

Explanation:

#(x-5)^2=4 or x-5 =sqrt4 or x-5 = +-2 or x=5+-2 :. x=7 or x=3#

Solution: #x=7 or x=3# [Ans]

Jun 15, 2017

Answer:

#x=3or x=7#

Explanation:

If #(x-5)^2=4#
then
#color(white)("XXX")x-5=+-sqrt(4)=+-2#

#{:("if " x-5=-2,color(white)("xxx"),"if "x=+2), ("then " x=3,,"then "x=7) :}#