# How do you solve x-5y=15 and 4x-3y=26 using substitution?

you can isolate $x$ from the first equation giving:
$x = 5 y + 15$ and substitute in the second:
$4 \left(5 y + 15\right) - 3 y = 26$
$20 y + 60 - 3 y = 26$
$17 y = - 34$
$y = - 2$
Substituting back in: $x = 5 y + 15$ it gives you:
$x = - 10 + 15 = 5$