# How do you solve ( x - 6)^2 = 19?

Apr 14, 2016

$x = 6 + \sqrt{19} , 6 - \sqrt{19}$

#### Explanation:

${\left(x - 6\right)}^{2} = 19$

Take the square root of both sides.

$x - 6 = \pm \sqrt{19}$

Add $6$ to both sides of the equation.

$x = 6 \pm \sqrt{19}$

Solve for $x$.

$x = 6 + \sqrt{19} , 6 - \sqrt{19}$