# How do you solve (x-6)(x+10)<0?

Sep 13, 2016

Solution is $- 10 < x < 6$.

#### Explanation:

As $\left(x - 6\right) \left(x + 10\right) < 0$, $\left(x - 6\right) \left(x + 10\right)$ is negative.

Hence,

either $\left(x - 6\right) < 0$ and $\left(x + 10\right) > 0$ i.e.$x < 6$ and $x > - 10$

which is true only if $- 10 < x < 6$

or $\left(x - 6\right) > 0$ and $\left(x + 10\right) < 0$ i.e.$x > 6$ and $x < - 10$, which cannot be true

Hence solution is $- 10 < x < 6$.