How do you solve #(x-7)^2=10#?

1 Answer
Gió
May 27, 2017

I got:
#x_1=7+sqrt(10)#
and
#x_2=7-sqrt(10)#

Explanation:

We could take the square root of both sides remembering that, for example, #4# can be obtained squaring either #2# or #-2# so we need to include these two possibilities:

#sqrt((x-7)^2)=+-sqrt(10)#

#x-7=+-sqrt(10)#

so that we get:

#x=7+-sqrt(10)#

i.e. two solutions:

#x_1=7+sqrt(10)#

and

#x_2=7-sqrt(10)#

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