# How do you solve (x-7)^2=10?

##### 1 Answer
May 27, 2017

I got:
${x}_{1} = 7 + \sqrt{10}$
and
${x}_{2} = 7 - \sqrt{10}$

#### Explanation:

We could take the square root of both sides remembering that, for example, $4$ can be obtained squaring either $2$ or $- 2$ so we need to include these two possibilities:

$\sqrt{{\left(x - 7\right)}^{2}} = \pm \sqrt{10}$

$x - 7 = \pm \sqrt{10}$

so that we get:

$x = 7 \pm \sqrt{10}$

i.e. two solutions:

${x}_{1} = 7 + \sqrt{10}$

and

${x}_{2} = 7 - \sqrt{10}$