# How do you solve (x-8)^2=4?

${\left(x - 8\right)}^{2} = 4 \implies \sqrt{{\left(x - 8\right)}^{2}} = \sqrt{4} \implies \left\mid x - 8 \right\mid = 2 \implies x - 8 = \pm 2 \implies {x}_{1} = 10 , {x}_{2} = 6$