# How do you solve x=8-2y and x=-3y+12?

##### 2 Answers

#### Answer:

First solve for

#### Explanation:

We're very lucky for this problem, as both expressions leave

Now, we can ignore

Since

Finally, we can solve for

#### Answer:

#### Explanation:

#x=8-2yto(1)#

#x=-3y+12to(2)#

#"since both equations express x in terms of y , equate"#

#"the right sides"#

#8-2y=-3y+12#

#"add "3y" to both sides"#

#8-2y+3y=12#

#"subtract 8 from both sides"#

#y=12-8=4#

#"substitute "y=4" into either of the 2 equations"#

#(1)tox=8-8=0#

#"the point of intersection "=(0,4)#

graph{(y+1/2x-4)(y+1/3x-4)=0 [-10, 10, -5, 5]}