How do you solve #x- 8\leq 4x + 7#?
1 Answer
Feb 20, 2017
Explanation:
collect x terms on right side of inequality and numeric values on the left side.
subtract x from both sides.
#cancel(x)cancel(-x)-8<=4x-x+7#
#rArr-8<=3x+7# subtract 7 from both sides.
#-8-7<=3xcancel(+7)cancel(-7)#
#rArr-15<=3x# To solve for x, divide both sides by 3
#(-15)/3<=cancel(3 x)/cancel(3)#
#rArr-5<=x" or " x>=-5#
