Question

How do you solve `x(x-4)-2=43`?

Answer 1

I would start by multiplying the `x` to get rid of the bracket:
`x^2-4x-2=43`
rearranging:
`x^2-4x-2-43=0`
`x^2-4x-45=0`
so that:
`x_(1,2)=(4+-sqrt(16-4(1*-45)))/2=(4+-sqrt(196))/2=(4+-14)/2`
So, you get two solutions:
`x_1=18/2=9`
`x_2=-10/2=-5`

:-)