# How do you solve #x+y= -3# and #x+y=3#?

##### 1 Answer

Aug 23, 2015

#### Explanation:

Your system of equations will have **no solution**.

You can think about this in two ways.

Notice that you have

#x+y = -3#

and the second equation has

#x+y = 3#

If you try to replace

#3 != -3#

An alternative approach is to notice that you're dealing with the equations of two lines. When you're solving a system of equations, you're essentially looking for the point in which those lines **intersect**.

In your case, these lines will never intersect because they are *parralel lines*.

graph{(y+x-3)(y+x+3)=0 [-10, 10, -5, 5]}