# How do you solve x - y = 4 and y = x² - 34?

For ${x}_{1} = 6 \implies {y}_{1} = 2$
For ${x}_{2} = - 5 \implies {y}_{2} = - 9$

#### Explanation:

$- y = - x + 4$ (1)
$y = {x}^{2} - 34$ (2)

$0 = {x}^{2} - x - 30$
${x}_{1} = 6$
${y}_{1} = {6}^{2} - 34 = 2$
${x}_{2} = - 5$
${y}_{2} = {\left(- 5\right)}^{2} - 34 = - 9$