How do you solve # y^2 - 3y - 14 = 0# using completing the square?
Add 14 to both sides, then add half the square of the coefficient of
1) Add 14 to both sides of the equation
2) Add half the square of
3) Now the left side is a perfect square; remember to simplify the right hand side too
5) Add the remaining fraction on the left to both sides and simplify your roots
The solution set is: