Question

How do you solve `y= 2 log(x)`?

Answer 1

`x=sqrt(10^y)`

Explanation:

`y= 2log x or y= log x^2; [log x^m=mlogx]`

`:. x^2=10^y :. x=sqrt(10^y );`

`[log _b (N)=x` , then `b^x=N]`

[Ans]