How do you solve #y=2x-3# and #y=-3x+2# using substitution?

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Answer 1 · 2016-05-18T17:11:07

The solution for the system of equations is:

#color(green)(x =1 #
#color(green)(y = - 1 #

#color(blue)(y = 2x - 3 #............equation #(1)#

#y = -3x + 2 #......equation #(2)#

Solving by substitution.

Substituting equation #1# in equation #2#:

#y = -3x + 2 #

#color(blue)( 2x - 3)= -3x + 2 #

#2x + 3x= 2 + 3 #

#5x= 5 #

#x = 5/5#

#color(green)(x =1 #

Finding the value of #y# from equation #1:#

#y = 2x - 3 #

#y = (2 * 1) - 3 #

#y = 2 - 3 #

#color(green)(y = - 1 #