# How do you solve y = 2x – 4 and 7x – 5y = 14?

Use substitution of the first equation into the second equation to ultimately get the unique solution $\left(x , y\right) = \left(2 , 0\right)$.
If you substitute $y = 2 x - 4$ into $7 x - 5 y = 14$, you'll get $7 x - 5 \left(2 x - 4\right) = 14$, which simplifies to $7 x - 10 x + 20 = 14$ and then $3 x = 6$ so that $x = 2$.
Now plug $x = 2$ back into $y = 2 x - 4$ to get $y = 2 \cdot 2 - 4 = 0$.
The unique solution is therefore the point $\left(x , y\right) = \left(2 , 0\right)$.