How do you solve #y/4 +2 = -1#?

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Answer 1 · 2018-04-24T12:11:48

#y = -12#

#=> y/4 + 2 = -1#

Subtract #2# from both the sides

#=> y/4\ cancel(+2)\ cancel(-2) = -1 - 2#

#=> y/4 = -3#

Multiply both sides by #4#

#=> y/cancel(4) × cancel(4) = -3 × 4#

#=> y = -12#

Answer 2 · 2018-04-24T12:17:53

#y=-12#

Solve:

#y/4+2=-1#

Multiply both sides by #4#.

#y/color(green)cancel(color(black)(4))^1xxcolor(green)cancel(color(red)(4))^1+2xxcolor(red)4=-1xxcolor(red)4#

Simplify.

#y+8=-4#

Subtract #8# from both sides.

#y+color(red)cancel(color(black)(8))-color(red)cancel(color(black)(8))=-4-8#

Simplify.

#y=-12#