How do you solve y=(5(10-y))/(3(y+1)) using the quadratic formula?

1 Answer
Jul 3, 2016

$y = \frac{50 - 5 y}{3 y + 3}$

$y \left(3 y + 3\right) = 50 - 5 y$

$3 {y}^{2} + 3 y = 50 - 5 y$

$3 {y}^{2} + 8 y - 50 = 0$

$y = \frac{- 8 \pm \sqrt{{8}^{2} - 4 \times 3 \times - 50}}{2 \times 3}$

$y = \frac{- 8 \pm \sqrt{664}}{6}$

$y = \frac{- 8 \pm 4 \sqrt{166}}{6}$

$y = \frac{- 4 \pm 2 \sqrt{166}}{3}$

Hopefully this helps!