# How do you solve #(y+5)(y-1)=27#?

##### 1 Answer

Mar 25, 2018

#### Explanation:

multiply the parentheses together

combine like terms

subtract 27 from both sides

figure out what numbers add to 4 and -32. It's -4 and 8

for the left side of the equation to equal zero, either y-4 or y+8 must equal zero (because zero times anything makes zero). y-4 is equal to zero when y = 4, and y+8 is equal to zero when y = -8. therefore,