How do you solve #y=x-5# and #4x+2y=8#?

1 Answer
Apr 1, 2018

#y = x - 5# is equation 1
#4x + 2y = 8# is equation 2
Substitute equation 1 into equation 2 where possible and is as follows:
#4x + 2(x - 5) = 8#
#4x + 2x- 10 = 8#
#4x + 2x = 8 +10#
#6x = 18#
#x = 18 / 6#
#x =3#
To find the value of y, substitute the value for x in equation 1 or 2 but I'll use equation 2 because it is easier and requires less calculations.
#y = x - 5#
#y = 3 - 5#
#y = -2#

#x = 3 ; y = -2#
#(3,-2)#