# How do you solve #z+ 8+ 3z \leq - 4#?

##### 1 Answer

Jun 13, 2018

#### Explanation:

First, we can change the order of addition on the left hand side to group all the variable

#z+3z+8 le -4#

Now, notice that

#4z+8 le -4#

In order to get

#4z+8-8 le -4-8#

#4z le -12#

Now, divide both sides of the inequality by

#(4z)/4 le (-12)/4#

#z le -3#

And that's your answer!