How do you square #((3, 1), (4, 2))#?

1 Answer
George C.
Jul 31, 2016

#((3,1),(4,2))^2=((13,5),(20,8))#

Explanation:

#((3,1),(4,2))^2#

#= color(red)(((3,1),(4,2)))color(blue)(((3,1),(4,2)))#

#= ((color(red)(3)*color(blue)(3)+color(red)(1)*color(blue)(4), color(red)(3)*color(blue)(1)+color(red)(1)*color(blue)(2)),(color(red)(4)*color(blue)(3)+color(red)(2)*color(blue)(4),color(red)(4)*color(blue)(1)+color(red)(2)*color(blue)(2)))#

#=((9+4,3+2),(12+8,4+4))#

#=((13,5),(20,8))#

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