How do you subract #7-4\frac { 1} { 9}#?

2 Answers

#2 8/9#

Explanation:

1)
i) First of all, we need turn all the mixed numbers and whole numbers (most commonly known as integers) into improper fractions (or top-heavy fractions as some might call them).

#4 1/9 => 37/9#

Remember to multiply the whole number by the denominator and add the numerator to the result.

eg: #(4*9) + 1#

ii) Turn 7 into an improper fraction.

#7/1 => 63/9#

2) Now that both denominators are equal. One simply has to subtract them.

#(63-37)/9 = 26/9#

3) All you need to do is convert this improper fraction to a mixed number.

#26/9 => 2 8/9#

Remember to divide the numerator by the denominator and to use the remainder as the new numerator.

eg: #26/9# is #2# remainder #8#. So #2# is the whole number and the #8# is the numerator.

Hope I helped!

Aug 2, 2017

#4 8/9#

Explanation:

Remember that any whole number is made up of a number of equal parts. #8/8, 13/13, 5/5, 10/10# are all whole numbers equal to #1#.

If you are subtracting a number of parts from a whole number, find how many parts are left.

#8/8 - 1/8 = 7/8" "rarr" "8# parts - #1# part = #7# parts

#11/11-3/11 = 8/11#

#23/23 - 10/23 = 13/23" "rarr 23 # parts - #10# parts = #13# parts

#3-1/7 = 2 6/7#

#19-3/11 = 18 8/11#

#5-3 1/5 = 5-3-1/5 = 2-1/5 = 1 4/5#

SO in this case, subtract #4# from #7#, then another #1/9#

#7-4 1/9 = 7-4-1/9#

#=5-1/9#

#4 8/9#