How do you subtract #4x - 6# from #2x + 8#?

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Answer 1 · 2018-01-27T17:02:02

See a solution process below:

We can write this problem as;

#(2x + 8) - (4x - 6)#

First, remove all of the terms from parenthesis. Be careful to handle the signs of each individual term correctly:

#2x + 8 - 4x + 6#

Next, group like terms:

#2x - 4x + 8 + 6#

Now, combine like terms:

#(2 - 4)x + (8 + 6)#

#-2x + 14#