How do you subtract #(- 8k ^ { 3} + 3k ^ { 2} - 4k - 9) - ( k ^ { 2} - 4k + 1)#?

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Answer 1 · 2017-06-03T23:45:08

See a solution process below:

First, remove all of the terms from parenthesis. Be careful to handle the signs of each individual term correctly:

#-8k^3 + 3k^2 - 4k - 9 - k^2 + 4k - 1#

Next, group like terms:

#-8k^3 + 3k^2 - k^2 - 4k + 4k - 9 - 1#

Now, combine like terms:

#-8k^3 + 3k^2 - 1k^2 - 4k + 4k - 9 - 1#

#-8k^3 + (3 - 1)k^2 + (-4 + 4)k + (-9 - 1)#

#-8k^3 + 2k^2 + 0k + (-10)#

#-8k^3 + 2k^2 - 10#